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If two zeroes of the polynomial x³×x-6x³-26x²+138x-35 are 2, + or - ?3. Find other zeroes.

As  are the zeroes of p(x), so  are the factors of p(x).

Dividing p(x) by x ² – 4x + 1

Hence, other two zeroes of p(x) are – 5 and 7.