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A STONE IS THROWN VERTICALLY UPWARD WITH AN INTIAL VELOCITY OF 40M/S. FIND THE MAXIMUM HEIGHT AND TIME OF ASCENT.
Acceleration of gravity is 9.8 m/s

  The stone continues to rise for (40/9.8) seconds. Then its speed is zero before it starts to fall.
Therefore time of ascent = 4.08seconds
During the ascent, average speed is 1/2 (40 + 0) = 20 m/s.

Distance straight up = (average speed) x (time of ascent) = 20 x (40/9.8) =81.63 meters


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