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A STONE IS DRAWN VERTICALLY UPWARD WITHIN INITIAL VELOCITY OF 40M/S FIND THE MAX. HEIGHT AND TIME OF ASCEND .g=9.8M/S.
Acceleration of gravity is 9.8 m/s

Ball continues to rise for (40/9.8) seconds. Then its speed is zero before it starts to fall.
Therefore the time of ascent = 40/9.8 = 4.08s
During the ascent, average speed is 1/2 (40 + 0) = 20 m/s.

Distance straight up = (average speed) x (ttime of ascent) = 20 x (40/9.8) =81.6 meters


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