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A BALL IS GENTLY DROPPED FROM A HEIGHT OF 20 m .IF ITS VELOCITY INCREASES UNIFORMILY AT THE RATEOF 10m/S2 WITH WHAT VELOCITY WILL IT STRIKE THE GROUND .AFTER WHAT TIME WILL IT STRIKE THE GROUND.AFTER WHAT TIME WILLIT STRIKE THE GROUND
 d = 20m
 a= g= 10m/s2
Time \ t\ taken for an object to fall distance \ d\ ==
\ t =\ \sqrt {\frac{2d}{g}} = sqrt(2*20/10) = 2sec.
Instantaneous velocity \ v_i\ of a falling object that has traveled distance \ d\ :\ v_i = \sqrt {2gd}\
= sqrt(2*10*20) = 20m/s


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