Ask a Teacher



A TRAIN IS TRAVELLING ATA A SPEED OF 90KM/HR .BRAKES ARE APPLIED SO AS TO PRODUCE A UNIFFORM ACCELERATION OF 0.5 M S-2.FIND HOW FOR THE TRAIN WILL GO BEFORE IT IS BOUGHT TO REST

Initial velocity, u  = 90km/h = 90 x 1000 / 3600 = 25m/s

Final velocity ,v = 0m/s

acceleration a = -0.5m/s

v^2 - u^2 = 2aS
S=(v^2 - u^2 )/2a
  =625m


comments powered by Disqus