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Two oxide of metal 'M' contain 50% and 75% oxygen respectively. The formula of first oxide is 'MO'. Then what will be the formula of second oxide. |
| Let the ratio of metal and oxide is a:b For the first oxide, a/b = 50/50 = 1:1 Formula = MO(given) For the second oxide,a/b = 75/25 = 3:1 Therefore formula = M30 |
