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CAN YOU DRAW A REGULAR POLYGON WITH EACH OF IT"S ANGLE IS EQUAL TO 47?

The measure of the interior angle of a regular polygon is:

theta = (n - 2) * 180 / n.

So for our case, we have:
47 = (n - 2) * 180 / n.

47n = 180n - 360
-133n = -360
n = 360/133

As 360/133 is not an integer, we conclude that there is no regular polygon with interior angle 47.


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