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Sir, please give me some questions related to velocity. |
1. A car travels a distance of 200 km from Delhi to
Ambala towards North in 5 hours. Calculate; speed, velocity of the car for this
journey. Answer: ( I ) Speed = Distance
travelled/Time taken = 200 km/5h = 40 km/h Thus, the speed ( or average speed) of the are in 40 km/h. (ii) Velocity =
Displacement/Time taken = 200 km towards North/5h = 40 km/h towards North So, the velocity ( or average
velocity) of the car is 40 km/h towards North.
2. A bus covers a distance of 250 km from the Delhi to
Jaipur towards west in 5 hours in the morning and returns to Delhi in the
evening covering the same distance of 250 km in the same time of 5 hours. Find
1. Average Speed and 2. Average Velocity of the bus for the whole
journey. Answer: a. Average speed = Total distance travelled/Total time
taken = 250 km + 250km/5h +
5h = 500 km/10h = 50 km/h. Thus, the average speed of
the bus for whole journey is 50 km/h.
b. In this case, the bus travels 250 km from Delhi 10
Jaipur towards west and is then comes back to starting point Delhi in the
reverse direction. So, the total
displacement will be 250km = 250 km = 0 km. Now, Average velocity = Total
displacement/Total time taken = 250 km
- 250km/5h + 5h = 0
km/10 h = 0 km/h Thus the average velocity of
the bus for the whole journey is 0 km
per hour.
3. A moving train is brought to rest within 20 records by
applying track. Find the initial
velocity, of the retardation due to track in 2m/s2 Answer: In this problem we have been given the
value of retardation but require the value of acceleration we known that retardation in
negative acceleration. So if the
retardation is +2m/s2, then the acceleration will be – 2m/s2. Here, Initial velocity, u = ? Final velocity, v = 0 Acceleration, a = -2m/s2 And time, t = 20s. We have v = u + at u = 40 m/s. Initial velocity of train is
40 m/s.
4. A wooden slab, starting from rest, slides down an
inclined plane of length 10m with an acceleration of 5 m/s. What would be its speed at the bottom of the
inclined plane? Answer: We have s = ut + ½ at 2 10 = ½ x 5 x t2 t = 2 s v = 0 + at = 5 x 2 = 10 m/s 5. Find the initial velocity of a train which is stopped
by in 20s by applying trakes. The retardation due to trakes in 1.5 m/s2 Answer: u = ? t= 20s v = 0 a = -1.5m/s2 v = u + at
6. An artificial satellite is moving in a circular orbit of radios nearly 42,250km. Calculate its linear velocity, if it takes 24 hours to revolve around the
earth. Answer: Linear velocity, V = Distance travelled/Time
taken = 2 ?rt = 2 x 22/7 x
42, 25/ 24 x 60 x 60 = 3.07 km/s 7. A car is travelling along the road at 8m/s. It
accelerates at 1m/s2 for a distance of 18m. How fast is travelling? Ans: Applying; v2 = u2 + 2 as
v2 = 64 + 2 x 8 v2 = 100 So, v
= 10m/s 8. A police jeep is chasing velocity of 45 km/h. A thief in another jeep moving with a velocity of 153 km/h. police fires a bullet with muzzle velocity of 180 m/s the velocity it will strike the car of the thief is? Ans: Given: Velocity of police jeep = 45 m/hr = 12.5 m/s Velocity of thief’s jeep = 153 km/hr = 42.5 m/s Velocity of bullet = 180 m/s Now, since bullet is fired from police jeep which is going at 42.5 m/s, Therefore, velocity of bullet is (180 + 12.5) = 192. 5 m/s. To calculate velocity with which bullet with hit the thief we use concept
of relative velocity. Therefore, we have VBT
= VB - VT Here VB is velocity of bullet and VT is velocity of thief VBT = 192. 5m/s - 42.5 m/s
= 150m/s |