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What is the volume occupied by 16g O2 at n.t.p |
| Molecular weight of O2 = 2 x 16= 32 g 32 g of O2 at NTP occupies = 22.4 L 16g of O2 at NTP = (22.4 * 16)/32g = 11.2L 16g of O2 at NTP occupies a volume of 11.2 L. |
