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If x+y+z=9 , find (3-x)^3+(3-y)^3+(3-z)^3-3(3-x)(3-y)(3-z) |
| a3+b3+c3=3abc if a+b+c=0 So a3+b3+c3-3abc =0 Hence (3-x)3+(3-y)3+(3-z)3-3(3-x)(3-y)(3-z)=0 |
