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Find a and b if x+1 and x+2 are factors of (x^3)+(3x^2)-2ax+b

Let p(x) =x3+3x2-2ax+b
Since x+1 is a factor, p(-1)=0
Since x+2 is a factor, p(-2)=0
Solving these two equations we get the value of a and b.


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