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3 resistors 1 ohm,2ohm,&3ohm are combined in series.if the combination is connected to a battery of emf 20v&negligible internal resistance,obtain the potential drop across each resistor |
Total resistance = 1+2+3 = 6 ohm Total current ,I = V/R = 20/6 = 3.33 ohm Potential drop across resistors V(1 ohm) = I * R= 3.33 * 1 = 3.33V V(2 ohm) = I *R = 3.33* 2 =6.66 V V(3 ohm) = I*R =3.33 * 3 = 9.99 V Note : series combination current will be same and voltage different parallel combination vice versa |