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consider the pattern given below square of 2-3=1 " " 3-6=3 " " 4-10=6 a)write the next 3 lines of this pattern. b)prove that if the sum of first n natural numbers is subtracted from the sum of the first n odd numbers we get sum of first (n-1)natural numbers
Sum of first n natural numbers = n(n +1)/2
Sum of first n odd numbers = n2
Their difference =  n2  - n(n +1)/2
                      = n(n - 1)/2,which is the sum of first (n - 1) natural numbers.


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