Ask a Teacher



the total no. of electrons present in 1l water (density 1g/ml)is

 The total number of electrons present in 1000mL of water (density of water is 1g mL-1) is

Sol.

     m/v = density
        m = density × v = (1g/mL) × 1000mL = 1000g
  moles = 1000/18 = 55.55 moles
No. of e– in 55.55 moles of H2O = (2 + 8)/55.55 = .18 moles of e–1 s = .18 × 6.023 × 1023
              =1.08 × 1023



comments powered by Disqus