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A train is traveling with a velocity of 72 km/h. The breaks are applied to retard the motion of the train uniformly. If the train stops after traveling 50 meters away from the place where the breaks were applied, find the retardation of the train.

u=72 km/h=72x 5/18 m/s
v=om/s
d=50m
t=50/20=2.5s
Retardation= -20/2.5=8m/s2


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