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A bullect of mass 20gm moving with a speed of 120m/s enters a heavy wooden block and is stopped after a distance of 1.2m.What is the average resistive force?
The initial velocity of the bullet is v0 = 120 m/s.As the bullet enters the wooden block,its velocity decreases to zero(ie., v = 0) after covering a distance of 1.2 m(ie., S = 1.2 m)

Now,v2 - v02 = 2aS
a = v0 - v02/2S
  = (0)2 - (120)2/2 x 1.2
  = - 6000 m/s
Therefore Average Retarding Force,F = ma
                                                          = 0.02 x 6000
                                                          = 120 N


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