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Calculate the weight of sodium sulphate required to prepare 1 kg of 0.2 moles of aqueous soln?

Given that , 0.2 mole wt of solvent(H2O) - 1kg

Solute - Na2SO4

M.wt : 2 x 23 + 32 + 4 x 16 = 142

...

x = 28.4 gms



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