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Factorize x^3-6x^2+11x-6 |
| Let P(x) = x3-6x2+11x-6 When x=1, p(1) = 0 So x-1 is a factor. Divide P(x) by x-1, we get, x2 - 5x + 6 = 0 ie, (x-3)(x-2)=0 Hence the factors are x-1, x-2, x-3 |
