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ABCD is a square. X and Y are points on sides AD and BC respectivly such that AY=BX. Prove that (i) BY=AX (ii) |
![]() In right triangles ABY and ABX, AY= BX (given) BA =AB (common) By RHS criterion, these two triangles are congruent. Hence by CPCT, By =AX and <BAY = <ABX |