Since the triangle is right-angled, cos? = b/c and sin? = a/c On squaring both we get cos2? = b2/c2 and sin2? = a2/c2 Adding together , cos2? + sin2? = (a2 + b2)/c2 Accodring to Pythagorus theorem a2 + b2 = c2 so (a2 + b2)/c2 = 1 Therefore cos2? + sin2? = 1