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Construct a triangle with sides 5cm, 6cm, and 7cm and then another triangle whose sides are 7/5 of the corresponding sides of the first triangle
Step - 1
Draw a line segment AB of 5 cm. Taking A and B as centre, draw arcs of 6 cm and 5 cm radius respectively. Let these arcs intersect each other at point C. ?ABC is the required triangle having length of sides as 5 cm, 6 cm, and 7 cm respectively.

Step - 2
Draw a ray AX making acute angle with line AB on the opposite side of vertex C.

Step - 3
Locate 7 points, A1, A2, A3, A4 A5, A6, A7 (as 7 is greater between 5and 7), on line AX such that AA1 = A1A2 = A2A3 = A3A4 = A4A5 = A5A6 = A6A7.

Step - 4
Join BA5 and draw a line through A7 parallel to BA5 to intersect extended line segment AB at point B'.

Step - 5

Draw a line through B' parallel to BC intersectingthe extended line segment AC at C'.
?AB'C' is the required triangle.


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