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5.6l of helium gas at STP is adiabatically compressed to 0.71.Taking the initial temperature to be T1,the work done in the process is

In an adiabatic process
  q = 0

Incase of compression

T2 > T1 
w = +ve     that is , the work is done on the system

Datas given

v1 = 5.6 l for dm3
v2 = 0.7 l or dm3
      = 7 w m3




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