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5.6l of helium gas at STP is adiabatically compressed to 0.71.Taking the initial temperature to be T1,the work done in the process is |
In an adiabatic process q = 0 ![]() Incase of compression T2 > T1 w = +ve that is , the work is done on the system Datas given v1 = 5.6 l for dm3 v2 = 0.7 l or dm3 = 7 w m3 ![]() |