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what is the oxidation numbers of Fe in Fe4[Fe(cn)6]?
The compound may be K4 [Fe (CN)6] / Na4 [Fe (CN)6]
If it is, K4 [Fe (CN)6], we know oxidation number for molecules/compounds is always zero

K4[Fe (CN)6] = 0
Oxidation number of K is + 1
Oxidation number of CN is - 1
K4 [Fe (CN)6] = 0

[Fe (CN)6 ] = - 4
Fe + 6 CN = - 4
Fe + 6 (-1) = - 4
Fe - 6 = - 4
Fe = - 4 + 6
     = + 2

The oxidation number of Fe is +2


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