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What point on x axis is equidistant from the pointsA(7,6)and B(-3,4)? |
Let A(7, 6), B(-3, 4) be the given points. Let P(x, 0) be the required point. Since p is equidistant from A and B, AP = BP implies AP2 = BP2 So, (x - 7)2 + (0 - 6)2 = (x+ 3)2 + (0 - 4)2 ie, x2 + 49 - 14x + 36 = x2 + 9 + 6x + 16 implies -20 x = -60 ie, x = -60/-20 = 3 Hence point on x - axis is (3, 0). |
