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A stone is thrown up with a velocity u vector which makes an angle teta with the horizontal a)What are the magnitudes of horizontal and vertical component of velocity? b)How do these components change with time? c)After 't' second what will be the magnitude and direction of the resultant velocity?
a)magnitude of horizontal velocity=ucos(teta)
  magnitude of vertical velocity=usin(teta)
b)Whenever the projectile is thrown or follows the trajectory, the horizontal component of the velocity does not change.
For the vertical component of the velocity during the projectile motion, change in both the magnitude and direction takes place.If the projectile is moving in the upward direction, then the vertical component of the velocity is in the upward direction and decrease in its magnitude takes place. On the other hand, when the projectile moves in the downward direction, the direction of the vertical components of the velocity is in the downward direction and increase in the magnitude takes place.
c)If Vx and Vy represents the magnitudes of horizontal and vertical components of velocity respectively,then resultant velocity,V=sqrt(Vx^2 + Vy^2).
direction is along the tangent of the projectile path.Tan(angle)=Vy/Vx.


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