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The range and maximum height of a projectile are equal. a)A boy can throw a ball to a maximum height 10m.What is the maximum horizontal distance to which he can throw? b)Arrive an expression to find the velocity of a projectile thrown with an initial velocity u. angle teta after 't' second? |
| a ) range or horizontal distance = 10 m b) max: height, hmax = v2/19.6 = 10 where v- initial velocity v = 14 m The resultant velocity of projectile motion motion at any time can be obtained as :  \  v = 14 m and g= 9.8 |
