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A thin wire 20 cm long is formed into a rectangle. If the width of the rectangle is 4 cm. What its length? Let the length of the rectangle = a cm The width of the rectangle = 4 cm Perimeter = L + B + L + B = a + 4 + a + 4 = 2a + 8. i didn't understand ? |
| Perimeter of the rectangle = 20 cm Perimeter of the rectangle = length + width + length + width Here width = 4 cm Hence 4 + 4 + length + length = 20 This is possible only when length = 6 cm |
