Ask a Teacher

Search



I have total of Rs 300 in coins of denomination Rs1,2,5 resp.The number of Rs 2 coins is 3 times the number of Rs 5 coins.The total no of coins is 160.How many coins of each denomination are with me

Let the no. of Rs. 5 coins be x and the no. of rs 1 coin be y and & no. of rs 2 coins be 3 x.

Total no. of coins = 160

x + 3x+y = 160

4x + y = 160 ..........(i)

again   total amount = 300

5x + 2(3x) + 1y = 300

11x + y = 300 ...............(ii)

by elimination method on subtracting both the equations,

  4x + y = 160

  -11x -y = -300

=>  -7x =-140

  x =20

on putting the the value of x in eqn (ii)

4(20) + y =160

80 + y = 160

y =80

now,

no of rs 2 coins = 3(20)

                      = 60

no. of rs 5 coins = 20

no. of rs 1 coins=80


comments powered by Disqus