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IF a,b,c length bredth & hight of acuboid such that a+b+c=10 and a2+b2+c2=40 cm2 find the surface area of cuboid

a+b+c=10
(a+b+c)2  =  a2 + b2 +c2 +2ab+2bc+2ac  (by an identity)

  (10)       =  40 +2(ab+bc+ca)

100 - 40       =  2(ab+bc+ca)

        60          =2(ab+bc+ca)

surface area of cuboid = 60cm2


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