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Find the probability that a non leap year chosen at random has a) 52 Sundays b) 53 Sundays

Let P(53) be the probability of 53 sundays in a non-leap year while P(52) be the probability of 52 sundays.

Now, There are 52 weeks in a year, So 52 sundays are certain in a year(non-leap)

Therefore The Probability of 53 Sundays remain on the last week, in which there are 7 days. Moreover Sunday would be anyone of them. So, Probabilities--->

P(52)=1(Its a certain event)

P(53)=1/7


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