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efficiency of packing in face-centred cubic cell &end -centred cubic cell? |
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PACKING FRACTIONSBoth of the above patterns of packing (i.e. hcp & ccp) though different in form are equally efficient. They occupy the maximum possible space which is about 74% of the available volume. Hence they are called closest packing. In addition to the above two types of arrangements a third type of arrangement found in metals is body centred cubic (bcc) in which space occupied is about 68%. CALCULATION OF THE SPACE OCCUPIED
Let ‘a’ be the edge length of the unit cell and r be the radius of sphere. As sphere are touching each other Therefore a = 2r No. of spheres per unit cell = 1/8 × 8 = 1 Volume of the sphere = 4/3 ?r3 Volume of the cube = a3= (2r)3 = 8r3 ? Fraction of the space occupied = 1/3?r3 / 8r3 = 0.524 ? % occupied = 52.4 % In face centred unit cell Let ‘r’ be the radius of sphere and ‘a’ be the edge length of the cube As there are 4 sphere in fcc unit cell ? Volume of four spheres = 4 (4/3 ?r3) In fcc, the corner spheres are in touch with the face centred sphere. Therefore, face diagonal AD is equal to four times the radius of sphere AD = 4r But from the right angled triangle ACD AD = ?AC2 + DC2 = ?a2 + a2= ?2a ?2a = 4r or a = 4/?2 r ? volume of cube = (4/?2 r)3 = 64 / 2?2 r3 percentage of space occupied by sphere = volume of sphere / volume of cube × 100 = 16/3 ?r3 / 64 /2?2 r3 × 100 = 74% As the sphere at the centre touches the sphere at the corner. Therefore body diagonal AD = 4r Face diagonal AC = ?AB2 + BC2 = ?a2 + a2 = ?2a In right angled triangle ACD = AD = ?AC2 + CD2 = ?2a2 + a2 = ?3a ?3a = 4r a = 4r / ?3 ? Volume of the unit cell = a3 = (4r / ?3)3 = 64r3 / 3?3 No. of spheres in bcc = 2 ? volume of 2 spheres = 2 × 4/3?r3 ? percentage of space occupied by spheres = volume of sphere / volume of cube × 100 = 8/3 ?r3 × 100 / 64r3 / 3?3 = 8/3 × 22/7 × 3?3/64 = 68% |