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efficiency of packing in face-centred cubic cell &end -centred cubic cell? |
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PACKING FRACTIONSBoth of the above patterns of packing (i.e. hcp & ccp) though different in form are equally efficient. They occupy the maximum possible space which is about 74% of the available volume. Hence they are called closest packing. In addition to the above two types of arrangements a third type of arrangement found in metals is body centred cubic (bcc) in which space occupied is about 68%. CALCULATION OF THE SPACE OCCUPIED
Let ‘a’ be the edge length of the unit cell and r be the radius of sphere. As sphere are touching each other Therefore a = 2r No. of spheres per unit cell = 1/8 × 8 = 1 Volume of the sphere = 4/3 ?r3 Volume of the cube = a3= (2r)3 = 8r3 ? Fraction of the space occupied = 1/3?r3 / 8r3 = 0.524 ? % occupied = 52.4 % In face centred unit cell Let ‘r’ be the radius of sphere and ‘a’ be the edge length of the cube As there are 4 sphere in fcc unit cell ? Volume of four spheres = 4 (4/3 ?r3) In fcc, the corner spheres are in touch with the face centred sphere. Therefore, face diagonal AD is equal to four times the radius of sphere AD = 4r But from the right angled triangle ACD AD = ?AC2 + DC2 = ?a2 + a2= ?2a ?2a = 4r or a = 4/?2 r ? volume of cube = (4/?2 r)3 = 64 / 2?2 r3 percentage of space occupied by sphere = volume of sphere / volume of cube × 100 = 16/3 ?r3 / 64 /2?2 r3 × 100 = 74% Let ‘r’ be the radius of sphere and ‘a’ be the edge length of the cube As the sphere at the centre touches the sphere at the corner. Therefore body diagonal AD = 4r Face diagonal AC = ?AB2 + BC2 = ?a2 + a2 = ?2a In right angled triangle ACD = AD = ?AC2 + CD2 = ?2a2 + a2 = ?3a ?3a = 4r a = 4r / ?3 ? Volume of the unit cell = a3 = (4r / ?3)3 = 64r3 / 3?3 No. of spheres in bcc = 2 ? volume of 2 spheres = 2 × 4/3?r3 ? percentage of space occupied by spheres = volume of sphere / volume of cube × 100 = 8/3 ?r3 × 100 / 64r3 / 3?3 = 8/3 × 22/7 × 3?3/64 = 68% |