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three unbiased coins are tossed.what is the probability of getting at most two heads?

Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}

Let E = event of getting at most two heads.

Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.

P(E) =  n(E)/n(S) = 7/8