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Find the sum of all natural numbers lying between 100 to 200 which are divisible by 4. |
| Required AP = 104, 108, 112, ......200. Here a = 104, d = 4, an = 200. an = a + (n - 1) d 200 = 104 + (n - 1) 4 200 = 104 + 4n - 4 4n = 100 n = 25 Sn = n/2 (a1 + an) = 25/2(104 + 200) = 25/2 x 304 = 25 x 152 = 3800 |
