Ask a Teacher
a person has a rectangular garden whose area is 100 sq m. he fences three sides of the garden with 30 m barbed wire. on the fourth side, the wall of his house is constructed, find the dimensions of the garden. |
Let the length and breadth if the rectangle be l m and b m respectively. Suppose the person builds his house along the length of the garden. Given, Area of the rectangular garden = 100 m2 ? lb = 100 ...(1) Length of the barbed wire = 30 m The barbed wire is fenced along the three sides of the garden, ? l + 2b = 30 ? l = 30 – 2b ...(2) From (1) and (2), we get (30 – 2b) b = 100 ?30b – 2b 2 = 100 ? b 2 – 30b + 100 = 0 ? b 2 – 15b + 50 = 0 ? b 2 – 10b – 5b + 50 = 0 ? b(b – 10) – 5(b – 10) = 0 ? (b – 10) (b – 5) = 0 ? b – 10 = 0 or b – 5 = 0 ? b = 10 or b = 5 When b = 10, we get l = 30 – 2b = 30 –2 × 10 = 30 – 20 = 10 When b = 5, we have l = 30 – 2b = 30 –2 × 10 = 30 – 10 = 20 Thus, the dimension of the garden is 10 m × 10 m or 20 m × 5 m. |