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From a solid cylinder whose height is 2.4cm and diameter 1.4cm,a conical cavity of the same height and same diameter is hollowed out.find the total surface area of the remaining solid. |
Given that, Height (h) of the conical part = Height (h) of the cylindrical part = 2.4 cm Diameter of the cylindrical part = 1.4 cm Therefore, radius (r) of the cylindrical part = 0.7 cm ![]() Total surface area of the remaining solid will be = CSA of cylindrical part + CSA of conical part + Area of cylindrical base ![]() ![]() |