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If a, b and c be the sums of first p, q and r terms respectively of an AP, show that a/p(q-r) + b/q(r-p) + c/r (p-q) = 0
Let A be the first term and D be the common difference of the given A. P.
a = sum of p terms

b = sum of q terms

c = sum of r terms

Multiplying equation (1), (2), (3) by (q – r); (r – p) and (p – q) respectively and adding,


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