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1. (1!) (1!) (1!)(1!)( ) 2. (1!) (1!) (1)(1)(1) 3. (1!) (1!) (1)(!)(1) here one (1) is the upper arrow and (!) this is the downward arrow...... among these above mentioned electronic configuration ,which one is correct ?
 2. Is correct. This is similar to the configuration of
 1S2     2S2        2Px  2Py   2Pz 
                        


Reason for 1 and 3 are wrong

1 is 1S2 2S2 2Px2 2Py2  is not possible,  because orbitals are first filled  halve and then fulfilled hence it will be 1S2     2S2        2Px2  2Py1  2Pz1


3. is wrong because spin of electron is uniform not random.
                


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