Ask a Teacher

Search



The electric field due to a positive charge at a distance 2m is 4N/C.Its magnitude at a distance of 4m will be_______________
electric field ,E = F/q
= kQ/r^2
Thus, electric field is directly proportional to 1/r^2.
when, r=2m,E=4N/C
so, kQ=16 Nm^2/C
when r=4m,
E= 16/4^2
= 16/16
= 1N/C.


comments powered by Disqus