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An electron is released in a region where the electric field is along the positive x direction and has a strength of 3600N/C.What is the acceleration of the electron in the electric field.
Force experienced by electron, F = eE
e= 1.6*10^-19 C, the charge of electron
E= 3600 N/C
We know, F= ma where m= 9.1*10^-31, the mass of electron
acceleration, a = F/m
= eE/m
= (1.6*10^-19*3600)/(9.1*10^-31)
= 633*10^12 N/kg.


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