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In an AP 5th and 12th terms are 30 and 65 respectively. What is the sum of first 20 terms |
We have an=a+(n-1)d Given a5=30 a+4d=30 ...(1) and a12=65 a+11d=65...(2) (2) - (1), 7d=35 d=5 Now from (1), a+20=30 a=10 For sum of n terms we have formula Sn=n / 2[2a+(n?1)d]; Put n=20, a=10 and d=5; S20=20/2[2*10+(20?1)5] =10[20+95] =1150 |