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will you please give some detailed class notes based on the chapter Gravitataion. |
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1.State the Universal law of Gravitation. Why do we say that the law is universal? The Universal law of Gravitation was given by Newton. So it is also known as Newton's Law of gravitation. According to Universal Law of Gravitation : Every body in the Universe attracts every other body with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. The law is universal because it is applicable to all objects; whether the objects are big or small,whether they are celestial or terrestrial. 2.What is the importance of Universal Law of Gravitation? 1. It is the gravitational force between the sun and the earth, which makes the earth to move around the sun with a uniform speed. Similarly, it is the gravitational force between the earth and the moon, which makes the moon to move around the earth with uniform speed. In fact, it is the gravitational force which is responsible for the existence of our solar system. 3. Derive the formula to find the magnitude of the gravitational force between two objects on the surface of the earth.
Consider two bodies A and B of masses m1 and m2 are lying at a distance r from each other. Let the force of attraction between these two bodies be F. Now, according to the Universal law of Gravitation.
4. Distinguish between Geocentric Theory and Heliocentric Theory.
5. What will happen to the gravitational force, a. When the distance between the two bodies is doubled? b. When the distance between the two bodies is halved? (a) F = Gm1m2/r2 F1= Gm1m2 / (2r)2 = F/ 4 The gravitational force becomes one fourth. (b) F= Gm1m2/ r2 F2 = Gm1m2 / (r/2)2 = 4F The gravitational force becomes four times. 6. What is the force of attraction due to a child of mass 20 kg and his mother of mass 100 kg. If the distance between them is 20cm? Take G = 6.67 x 10-11 Nm2/ kg2. Given m = 20kg M = 100kg F = GmM/r2 = 6.67 x 10-11x 20 x 100 / (20/100)2 = 6.67 x 10-11 x 2000 x 25 / 1 = 3.335 x 10-6 N 7. The mass of the earth is 6 x 1024 kg and that of the moon is 7.4 x 1022 kg. If the distance between the earth and the moon be 3.84 x 105 km. Calculate the force exerted by the earth on the moon. (G = 6.67 x 10-11 Nm2/kg2). The force exerted by one body on another body is given by the Newton's formula: F = Gm1m2/r2 Here, mass of earth, m1= 6 x 1024 kg mass of the moon, m2 = 7.4 x 1022 kg And, Distance between the earth and moon, r = 3.84 x 105 km = 3.84 x 105 x 1000 m = 3.84 x 108m Putting these values in the above formula, we get F = 6.67 x 10-11 x 6 x 1024 x 7.4 x 1022 / (3.84 x 108)2 = 2.01 x 1020 N 8. Define acceleration due to gravity. The uniform acceleration produced in a freely falling body due to the gravitational fore of the earth is known as acceleration due to gravity and it is denoted by the letter g.The value of g does not depend on the mass of the body. The value of g changes slightly from place to place but for the most of the purposes it is taken as 9.8m/s2. Thus, the acceleration due to gravity, g = 9.8m/s2. 9. Difference between mass and weight.
10. What is the ratio of SI units to CGS units of gravitational constant? SI unit of G is Nm2kg-2 CGS unit of G is dyne cm2g-2 The required ratio is Thus, the ratio of SI unit to CGS unit of G is 103.
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