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find k if zeroes of polynomial Kx2-6x+9 are equal |
| Let the zeroes = a and b a + b = -(-6)/k -2a = - 6/k -a = 6/2 k a(a) = 9 / k -k = 9/a2 -k = 9/(2k/6)2 -k = 9/4k2 / 36 -k = k2 -k 2 / k = 1 therefore k = 1 |
