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A cheetah is the fastest land animal and it can achieve a peak velocity of 100km/h upto a distance less than 500 m.if the cheetah spots it's prey at a distance of 100m ,what is the minimum time to get there
Solution :
           peak speed of cheetah = 100 km/hr
                    First  we will convert the speed into m/s
                                 therefore ,
                                 100 km/hr = 100 *1000 m / 60 *60
 ( because 1km = 1000 m and 1hr = 60 mimutes and 1 minute = 60 seconds )
                                 100km/hr = 100*5/18 m/s
                                               = 500 /18 m/s
                 Therefore , Peak speed of  Cheetah =  500/18 m/s
                    Distance between cheetah and its prey = 100 m
  Therefore ,
              time taken by cheetah to reach its prey at a distance of 100 m  =  distance between cheetah and prey / velocity of cheetah
                                                    = 100 /( 500/18) seconds
                                                     = 100*18/500
                                                     = 18/5
                                                     = 3.6 seconds


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