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The age of a man is twice the square of age of his son. Eight years hence, the age of the man will be 4 years more than 3 times the age of his son, find their present age
Son's present age = 4 years, and

man's present age = ( 2 × 4² ) years = 32 years .

→ Let the present age of the son be x years .

→ Then, the present age of the man is ( 2x² ) years .

→ Age of the son 8 years hence = ( x + 8 ) years .

→ Age of the man 8 years hence = ( 2x² + 8 ) years .

▶ Now,

•°• Son's present age = 4 years, and

man's present age = ( 2 × 4² ) years = 32 years .


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