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how to calculate the enthalpy of formation of HCL,the bond enthalpy of H-H,CL-CL,andHCL bonds are435,243 and 431KJ.respectively?

The chemical reaction of the formation of HCl can be written as ,
  H2   +Cl2  ___________> 2HCl
Enthalpy of formation of  HCl =  bond enthalpy of products  -bond enthalpy of reactants 
                                              =   2  x  431  -(435   +243  )
                                              =   862   -678
                                               =   190
                                     


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