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calculate the enthalpy of formation of HCL,the bond enthalpy of H-H, CL-CL,and HCL bpnds are435,243 and431KJ.respectively
The chemical reaction of the formation of HCl can be written as ,
  H2   +Cl2  ___________> 2HCl
Enthalpy of formationof HCl =  bond enthalpy of products  -bond enthalpy of reactants 
                                    =   2  x  431  -(435   +243  )
                                    =   862   -678
                                     =   190
                                     


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