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Show that any four vertices of a regular pentagon form a cyclic quadilateral. |
Let ABCDE a regular pentagon. It is required to show ABCD is a cyclic quadrilateral. In ?AED, AE = ED (Sides of regular pentagon ABCDE) ? ?EAD = ?EDA In ?AED, ?AED + ?EAD + ?EDA = 180 ? 108 + ?EAD + ?EAD = 180 ? 2?EAD = 180– 108 = 72 ? ?EAD = 36 ? ?EDA = 36 ?BAD = ?BAE – ?EAD = 108 – 36 = 72 In quadrilateral ABCD, ?BAD + ?BCD = 108 + 72 = 180 ?ABCD is a cyclic quadrilateral |