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A stone of mass 'm' is dropped from a height 'h' m downward. (i) Calculate the kinetic energy with which it reaches the ground? (ii) Name the principle you applied to get the answer?
kinetic energy = 1/2 x mass x velocity^2
As the body falls  the kinetic energy increases while the potential energy decreases.
Suppose that the mass falls from height h1 to h2,

            at the ground the potential energy, P E =  m x g x 0 (h = 0)

           ie, potential energy is zero.
           kinetic energy  
By using the third equation of motion to obtain velocity ,
           v2 - u2 = 2aS ,  Here u = 0, a = g and S = h
           

            

             

        Kinetic energy

         ie,when the free falling body reaches ground its ,

                       kinetic energy = potential energy.

                                      It is a validation of law of conservation energy.


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