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5 YEARS AGO A MAN WAS FOUR TIMES AS OLD AS HIS SON.AFTER 6 YEARS,HIS AGE EXCEEDS TWICE HIS SON'S AGE BY 17 YEAR. FIND THEIR PRESENT AGES. |
Let present age of man be x and that of son be y. 5 years ago, age of man = x - 5 age of son = y-5 According to the given condition, x - 5 = 4(y - 5) ie , x - 4y = -15---------(1) After 6 years, age of man = x + 6 age of son = y + 6 According to the given condition, x + 6 - 2(y + 6) = 17 ie, x - 2y = 23---------(2) (2) - (1) gives 2y = 38 implies y = 19 from (1), x = 61 Hence present age of man = 61 and present age of son = 19. |